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Old 12-23-10, 02:46 PM   #182
Forensicman101
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Join Date: May 2010
Location: Abercarn, South Wales, UK
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As long as you are attacking the target so that your torpedoes are striking at 90 degrees off the target's bow the calcuations are quite straightforward with a bit of basic trigonometry (I've included a table for this in my "Double Whammy" document). e.g. a 45.5 kt torpedo being fired at a 12 kt target would have to be fired when the target was approximately 15 (actually 14.8) degrees off the submarine's bow in such circumstances. As always, the trick is to remember that you're not firing at a target, but at where the target will be when your torpedo arrives at the same location. I guess the real difficulties arise when the point of intercept is greater or less than 90 degrees. I suppose that's where the fruit machine comes into play.
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